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5x^2-5x-3.75=0
a = 5; b = -5; c = -3.75;
Δ = b2-4ac
Δ = -52-4·5·(-3.75)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-10}{2*5}=\frac{-5}{10} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+10}{2*5}=\frac{15}{10} =1+1/2 $
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